This question was previously asked in

DSSSB PGT Commerce Male General Section - 28 June 2021 Noon

Option 3 : 14 cm

**Given:**

The radius of the solid sphere is 7 cm

The height of the pyramid is 22 cm

**Concept:**

The volume of square based pyramid = (1/3) × (The area of base) × Height

The volume of sphere = (4/3) × π × (The radius of the sphere)^{3}

**Calculation:**

When we recast any solid in another solid then the volume is always the same.

Let be assume the side of the square base of the pyramid is A

⇒ The volume of sphere = (4/3) × (22/7) × (7)^{3} = (4 × 22 × 49)/3 = 4312/3

⇒ The volume of the pyramid = (1/3) × A^{2} × 22 = (22A^{2})/3

⇒ (22A2)/3 = 4312/3

⇒ A^{2} = 4312/22 = 196

⇒ A = 14 cm

**∴ The required result will be 14 cm.**